Penn Foster Veterinary Pharmacology Practice Exam

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Question: 1 / 730

What is the volume required for a 44-lb dog that is 6% dehydrated and losing 100ml of fluid daily?

1200 mL

1800 mL

2520 mL

To determine the volume required for a dog that is 6% dehydrated, we first need to calculate the total fluid deficit due to the dehydration. The dog's weight is 44 lbs, which we convert into kilograms since fluid calculations are typically done in metric units.

1 lb is approximately 0.45 kg, so:

44 lbs x 0.45 kg/lb = 19.8 kg.

Next, we find the fluid deficit:

6% dehydration means the dog is missing 6% of its body weight in fluids. Therefore, we calculate:

6% of 19.8 kg = 0.06 x 19.8 kg = 1.188 kg.

Since 1 kg of water is equivalent to 1000 mL, this becomes:

1.188 kg x 1000 mL/kg = 1188 mL.

Next, we need to account for the daily fluid loss of 100 mL. If the dog is losing 100 mL of fluid daily, this loss needs to be replaced over a specific timeframe. If the goal is to determine the total volume this dog requires per day (which includes replacing both the fluid deficit and daily losses), we add the daily loss to the

Penn Foster Veterinary Pharmacology Practice Exam

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